# My Very Own ABC Triple

I like the abc conjecture. It says that numbers that are multiplicatively pretty can’t be too closely additively related, in a very precise mathematical way.

The conjecture is about abc triples and a function called the “radical”.

The radical of an integer is the product of its prime factors. For instance, radical(800) = 10.

Consider a triple a + b = c, where radical(abc) < c. For instance, 1 + 8 = 9, and radical(72) = 6 < 9. We call such a triple an abc triple. The quality of an abc triple is

```
log(c)/log(radical(abc))
```

For instance, the quality of 1 + 8 = 9 is log(9)/log(6) = 1.23.

The abc conjecture says that the limsup of quality over all abc triples, as c goes to infinity, is 1. In other words, for any epsilon > 0, the number of abc triples with with quality at least 1 + epsilon is finite.

There’s a website where you can use your computer to find fresh abc triples. I used it, and found the following three abc triples:

```
64009 + 282361946544470016 = 282361946544534025,
q=1.0075342812802697
167521249 + 7015842132869376 = 7015842300390625,
q=1.2556682988478818
15177592680649 + 75611195698334976 = 75626373291015625,
q=1.0206163223672695
```

I was interested in the middle abc triple, because its quality is so high. Let’s do some factorization:

```
167521249 + 7015842132869376 = 7015842300390625
12943^2 + 83760624^2 = 83760625^2
(7 * 43^2)^2 + (2^4 * 3^2 * 719 * 809)^2 = (5^4 * 13^3 * 61)^2
```

As a result, my radical(abc) is

```
2 * 3 * 5 * 7 * 13 * 43 * 61 * 719 * 809
= 4165223880090
< 7015842300390625
```

As you can see, radical(abc) is 3 digits shorter than c, so this is an abc triple!

This triple has a very special form. It’s a Pythagorean triple:

```
a = x^2, b = y^2, c=z^2, x^2 + y^2 = z^2.
```

Moreover, it’s a Pythagorean triple where y and z differ by 1, helping keep x small.

We can construct such a special Pythagorean triple for any odd x. Let x = 2d + 1. Then these special Pythagorean triples are of the form

```
x = 2d+1
y = 2d^2 + 2d
z = 2d^2 + 2d + 1
x^2 + y^2 = (2d+1)^2 + (2d^2 + 2d)^2
= 4d^2 + 4d + 1 + 4d^4 + 8d^3 + 4d^2
= 4d^4 + 8d^3 + 8d^2 + 4d + 1
z^2 = (2d^2 + 2d + 1)^2
= 4d^4 + 8d^3 + 4d^2 + 4d^2 + 4d + 1
= 4d^4 + 8d^3 + 8d^2 + 4d + 1
```

Are these special Pythagorean triples often abc triples? I’ll pick a random 4-digit number for d to find out. My random number generator gave me d=2201. This gives rise to the following triple:

```
x = 4403
y = 9693204
z = 9693205
a = 19386409
b = 93958203785616
c = 93958223172025
radical(abc)
= 3390967327436430
> 93958223172025
```

It’s close, but it’s not an abc triple. Let’s try again, but this time choose a d such that x is very, very factorizable. I picked d = 3280, which gives the following triple:

```
43046721 + 463255025689600 = 463255068736321
(3^8)^2 + (2^5 * 5 * 17 * 41 * 193)^2 = 21523361^2
radical(abc)
= 86860321352430
< 463255068736321
quality = 1.052156400142
```

I found an abc triple, this time by hand!

But my favorite is still the one that my computer found:

```
167521249 + 7015842132869376 = 7015842300390625
(7 * 43^2)^2 + (2^4 * 3^2 * 719 * 809)^2 = (5^4 * 13^3 * 61)^2
```

I really like the wide variety of small prime factors that it uses. Thanks for exploring abc triples with me!